Select Distinct date and Count

Question

My sample table structure is:

TestDate
----------------------
2013-03-25 14:26:40.830
2013-03-20 13:37:39.763
2012-09-10 14:55:55.667
2013-03-20 13:33:20.480

And my query is :

SELECT DISTINCT 
    REPLACE(RIGHT(CONVERT(VARCHAR(20), TestDate, 106), 8), ' ', '-') AS  TT
    ,(SELECT COUNT(*) 
      FROM Test bp 
      WHERE 
        CONVERT(VARCHAR(20), p.TestDate, 6) = CONVERT(VARCHAR(20), bp.TestDate, 6)) AS Posts 
 FROM Test p

I got a result:

TT         Posts
Mar-2013    1
Mar-2013    2
Sep-2012    1

But I want a result:

TT         Posts
Mar-2013    3
Sep-2012    1

But I am unable to find my mistake in my query. Thanks.

Answer 1

Are you trying to select the rows and count for each month?

If so - try something like this:

SELECT  
   YEAR(Testdate), MONTH(Testdate),
   COUNT(*) totalPost
FROM    
   tableName
GROUP BY
   YEAR(Testdate), MONTH(Testdate)

Update: if you insist on formatting that inside SQL Server (which I think is the wrong place to do this...) - then use something like this:

SELECT DISTINCT
   SUBSTRING(DATENAME(MONTH, TestDate), 1, 3) + '-' + CAST(YEAR(TestDate) AS VARCHAR(4)),
   YEAR(Testdate), MONTH(Testdate),
   TotalPosts = COUNT(*) 
FROM    
   tableName
GROUP BY
   SUBSTRING(DATENAME(MONTH, TestDate), 1, 3) + '-' + CAST(YEAR(TestDate) AS VARCHAR(4)),
   YEAR(Testdate), MONTH(Testdate)
ORDER BY
   YEAR(Testdate), MONTH(Testdate)

Answer 2

You need to cast DATETIME into DATE first.

SELECT  CAST(TestDate AS DATE) DATE_ONLY,
        COUNT(*) totalPost
FROM    tableName
GROUP   BY  CAST(TestDate AS DATE)