I have a list that goes like this:
name = ['road', 'roadwork', 'roadblock', 'ball', 'football', 'basketball', 'volleyball']
Is there a code that separate the compound nouns from the basic nouns? So that I can get:
name = ['road', 'ball']
Thanks.
All words that do not include any other words as a substring:
>>> [x for x in name if not any(word in x for word in name if word != x)]
['road', 'ball']
One way to print names using loops:
for candidate in name:
for word in name:
# candidate is a compound if it contains any other word (not equal to it)
if word != candidate and word in candidate:
break # a compound. break inner loop, continue outer
else: # no breaks occured, must be a basic noun
print candidate
names = ['road', 'roadwork', 'roadblock', 'ball', 'football', 'basketball', 'volleyball']
basic_names = [name for name in names if not any([part for part in names if part in name and part != name])]
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