How to pass the arguments to the shell script

Question

I want to pass the argument in the console while running a script called run.sh as follows

run.sh first count

for example:

./run.sh first 10

i have to pass those first and 10 to the script here

cat file1.txt | head -10

here first should refer to head and count value should be 10. how can i do this?

Answer 1

Use Positional Parameters

Bash supports positional parameters . Parameters one through nine are stored in $1 .. $9 , but you can have more stored in $ * or $@ .

For example:

#!/bin/bash

# Read x lines from some arbitrary file. 
head -n "$2" "$1"