I'll do my best to explain i create a query to return rows for a search function ex : return row WHERE id LIKE = _ _
here's my code :
if(!empty($champs)){
$table[0]["prog"] = array('mydb.message','Message');
$table[1]["prog"] = array('mydb.newtable','Username','nom','prenom');
as the table and columns to look into
$nb_result =0;
for($i =0 ; $i < count ($table); $i++)
{
$prog_tab = $table[$i]["prog"];
$sql = sprintf("SELECT *
FROM %s
WHERE 1 ",
$prog_tab [0],
DEFAULT_ACCESS_LEVEL);
for($j = 1; $j < count ($prog_tab ); $j++)
{
$sql .= sprintf(" OR %s LIKE '%s' ",
$prog_tab [$j],
$this->ins_string("%".$champs."%"),
DEFAULT_ACCESS_LEVEL);
}
echo $sql;
/*$sql = $table[$i]["user"][0] . ' ---> ' . $sql."<br>"; */
$query = mysql_query($sql) or die(mysql_error());
while($rows = mysql_fetch_array($query)){
if($table[$i]["prog"][1] == "Message"){
echo $rows['Sender']." :  ".$rows['Message']."<br />";
}
else{
echo $rows['Username']." ".$rows['nom']." ".$rows['prenom']."<br />";
}
}
$nb_result += mysql_num_rows($query);
}
echo "<br /><h1>".$nb_result."</h1>";
}
the problem is when i display the query it returns all the rows from my 2 tables and just ignore the LIKE %$champs%
NOTE* when i display the query it seems fine : SELECT * FROM mydb.newtable WHERE 1 OR Username LIKE '%$champs%' OR nom LIKE '%$champs%' OR prenom LIKE '%$champs%'
and $nb_result always returns 48 (amount of rows i have in the two tables combined )
A where
clause basically boils down a boolean decision for the database, "include this row, or don't include it". Since you're doing
SELECT ... WHERE 1 OR ... OR ... OR ...
^--
you're ALWAYS producing a 'true' value, so all rows will match and be included.
Remember your boolean truth tables. true OR anything
is true.
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