I have: "0xE94C827CEB" in hex but as a string.
Which is: 1002011000043 (dd mm yyyy HH mm ss)
Unfortunately I don't know how to do the conversion if I only have it in string format, and I don't have a Convert.ToLong("0xE94C827CEB", 16) function because I'm using the .NET Micro Framework (also, don't have NumberStyles namespace available.)
Is there a function out there that will convert this for me?
Thanks
For those of you looking for the answer using the full .NET framework for pc.
long answer = Convert.ToInt64("E94C827CEB",16);
see: MSDN Documentation
I don't know of any function to do it, but I think you can do it quite simply by splitting the hex string and passing each part through Convert.ToInt32():
int part1 = Convert.ToInt32("E9", 16)
int part2 = Convert.ToInt32("4C827CEB", 16) //the last 4 bytes
long result = part1 * 4294967296 + part2 //4294967296 being 2^32. Result = 1002011000043
Kick it old-school and roll your your own. This is not exactly rocket science here:
public ulong HexLiteral2Unsigned( string hex )
{
if ( string.IsNullOrEmpty(hex) ) throw new ArgumentException("hex") ;
int i = hex.Length > 1 && hex[0]=='0' && (hex[1]=='x'||hex[1]=='X') ? 2 : 0 ;
ulong value = 0 ;
while ( i < hex.Length )
{
uint x = hex[i++] ;
if ( x >= '0' && x <= '9' ) x = x - '0' ;
else if ( x >= 'A' && x <= 'F' ) x = ( x - 'A' ) + 10 ;
else if ( x >= 'a' && x <= 'f' ) x = ( x - 'a' ) + 10 ;
else throw new ArgumentOutOfRangeException("hex") ;
value = 16*value + x ;
}
return value ;
}
using the bit shift operators can clean up some of this code --
static long HexToLong(string hexString)
{
if (!string.IsNullOrWhiteSpace(hexString))
{
hexString = hexString.Trim();
if (hexString.StartsWith("0x"))
hexString = hexString.Substring(2);
if (hexString.Length > 16)
throw new FormatException("Input string is too long");
hexString = hexString.PadLeft(16, '0'); // ensure proper length -- pad the leading zeros
int part1 = Convert.ToInt32(hexString.Substring(0, 8), 16); // first 4 bytes
int part2 = Convert.ToInt32(hexString.Substring(8, 8), 16);//the last 4 bytes
return (part1 << 8 * 4) + part2; // slide it on over -- 8 bits per byte
}
return 0;
}
There you go
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