Display SQL query results in php

Question

I was trying to calculate the total of each column in the database and display it on the webpage using php. But it just gives me

Array
(
    [0] => 6
    [sum(food1)] => 6
)

which I just want '6' as my result.

Here is my code

for($i=1; $i<=10; $i++){
    $foodid=('food'."$i");
    echo $foodid;
    $food_query = mysql_query("select sum($foodid) from orderdetail where date between '$fm_date' and '$to_date'");
    $ttl_food= mysql_fetch_array($food_query);
    print_r($ttl_food[$i]);
}

Thanks so much!

Answer 1

The result of SELECT SUM or any other functions like COUNT() , MAX() etc. is always a recordset. You need to just take the first element of the array of rows (even if only one row exists). Just $your_rows_array[0] .

To avoid having strange names like [sum(food1)] you can SELECT SUM($foodid) AS mysum FROM ... .

Answer 2

Try below one by giving an alias name sumoffood to your aggregate function's output

$food_query = mysql_query("select sum($foodid) as sumoffood from orderdetail where date between '$fm_date' and '$to_date'");

and then use

$ttl_food= mysql_fetch_assoc($food_query);
echo $ttl_food['sumoffood'];

Answer 3

use

select sum(field) as sum

and

ttl_food['sum'];

Answer 4

Try this:

for($i=1; $i<=10; $i++){
$foodid=('food'."$i");
echo $foodid;
$food_query = mysql_query("select sum(field) as sum from orderdetail 
where date between '$fm_date' and '$to_date'");
$ttl_food= mysql_fetch_array($food_query);
print_r($ttl_food['sum']);