Insert data from XML file into MySql DB
Question
Hello i got problem with something, here it is i have to load xml file which has over 2000 properties, here you can find the structure of the file
and i'm using the fallowing code
<html>
<head>
<title>Insert Record</title>
</head>
<body>
<?php
ini_set('display_errors', 1);
ini_set('log_errors', 1);
ini_set('error_log', dirname(__FILE__) . '/error_log.txt');
error_reporting(-1);
include ('config.php');
$url = "http://admin.resales-online.com/live/Resales/Export/XMLFeed.asp?U=RESALES@MOVE2S&P=KKPDRT6986NG&n=100";
try{
$xml = new SimpleXMLElement($url, null, true);
}catch(Exception $e){
echo $e->getMessage();
exit;
}
$sql = 'INSERT INTO properties (`id`,`status_date`,`status`,`listed_date`,`last_updated`,`price`,`currency`,`country`,`province`) VALUES ';
foreach($xml->property as $property){
$sql .= sprintf("\n",
mysql_real_escape_string($property->id),
mysql_real_escape_string($property->status_date),
mysql_real_escape_string($property->listed_date),
mysql_real_escape_string($property->last_updated),
mysql_real_escape_string($property->price),
mysql_real_escape_string($property->currency),
mysql_real_escape_string($property->country),
mysql_real_escape_string($property->province)
);
}
$sql = rtrim($sql, ',') . ';';
if(!mysql_query($sql)){
echo '<h1 style="color: red;">Error</h1><p>', mysql_error(), '</p>';
}
?>
</body>
</html>
and i got this error
Error
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1
Please if anyone knows what might be the problem answer me here :)
Thank you
2 answers
solution1
0 2013-06-05 16:41:15
This is the format for an INSERT:
INSERT INTO table_name (column1,column2,column3,...)
VALUES (value1,value2,value3,...);
Where are your opening and closing parentheses for VALUES?
solution2
0 2013-06-05 16:42:50
Each of the values in the query are missing single quotes, and you're missing the opening and closing parenthesis. The proper syntax for an INSERT is:
INSERT INTO `table` (`field1`, `field2`, `field3`) VALUES ('value1', 'value2', 'value3')
Yours will look more like:
INSERT INTO `table` (`field1`, `field2`, `field3`) VALUES value1, value2, value3
The easiest way to debug is to echo out your $sql varaible so you can see what it looks like so you can quickly spot obvious errors.
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