AWK print specific line based on search pattern

Question

I have two sets of files test.csv data.xml.

I am trying to grep a specific field from test.csv and search the string in data.xml. If string is found then print the corresponding line in test.csv file.

Example

search string is field 3 server name

test.csv

111,xxx,serversugar,port90
222,yyy,servertorque,port190
333,aaa,serverastrix,port8080
422,yxy,servertorque,port290

data.xml

<group>
<hostname>servertorque</hostname>
<hostname>serverastrix</hostname></group>

Output expected

222,yyy,servertorque,port190
333,aaa,serverastrix,port8080
422,yxy,servertorque,port290

Answer 1

One way with awk

awk -v FS="[><,]" 'NR==FNR{a[$3]++;next}$3 in a' data.xml test.csv

Test:

$ cat data.xml
<group>
<hostname>servertorque</hostname>
<hostname>serverastrix</hostname></group>

$ cat test.csv
111,xxx,serversugar,port90
222,yyy,servertorque,port190
333,aaa,serverastrix,port8080
422,yxy,servertorque,port290

$ awk -v FS="[><,]" 'NR==FNR {a[$3]++;next} $3 in a' data.xml test.csv
222,yyy,servertorque,port190
333,aaa,serverastrix,port8080
422,yxy,servertorque,port290

Answer 2

with GNU sed & grep in 2 steps

sed '/>\w\+</!d;s/.*>\(\w\+\).*/\1/' data.xml>pattern.txt
grep -wf pattern.txt test.csv

..output:

222,yyy,servertorque,port190
333,aaa,serverastrix,port8080
422,yxy,servertorque,port290

Answer 3

我假设你需要：

awk -F',' '$3==<string_you_need> { print $0 }' test.csv