semantics of generating symmetric matrices in numpy

Question

I tried to make a random symmetric matrix to test my program. I don't care about the data at all as long as it is symmetric (sufficient randomness is no concern at all).

My first attempt was this:

x=np.random.random((100,100))
x+=x.T

However, np.all(x==xT) returns False. print x==xT yields

array([[ True,  True,  True, ..., False, False, False],
   [ True,  True,  True, ..., False, False, False],
   [ True,  True,  True, ..., False, False, False],
   ..., 
   [False, False, False, ...,  True,  True,  True],
   [False, False, False, ...,  True,  True,  True],
   [False, False, False, ...,  True,  True,  True]], dtype=bool)

I tried to run a small test example with n=10 to see what was going on, but that example works just as you would expect it to.

If I do it like this instead:

x=np.random.random((100,100))
x=x+x.T

then it works just fine.

What's going on here? Aren't these statements semantically equivalent? What's the difference?

Answer 1

Those statements aren't semantically equivalent. xT returns a view of the original array. in the += case, you're actually changing the values of x as you iterate over it (which changes the values of xT ).

Think of it this way ... When your algorithm gets to index (3,4) , it looks something like this in pseudocode:

x[3,4] = x[3,4] + x[4,3]

now, when your iteration gets to (4,3) , you do

x[4,3] = x[4,3] + x[3,4]

but, x[3,4] is not what it was when you started iterating.

---

In the second case, you actually create a new (empty) array and change the elements in the empty array (never writing to x ). So the pseudocode looks something like:

y[3,4] = x[3,4] + x[4,3]

and

y[4,3] = x[4,3] + x[3,4]

which obviously will give you a symmetric matrix ( y .