Python arguments passed with quotes

Question

I'm trying to pass file list to my python script via argument:

python script.py -o aaa -s bbb "filename.txt" "filename2.txt" "file name3.txt"

Unfortunately ArgumentParser is ignoring quotes and instead of giving list of 3 files it gives me list of 4 elements as followed:

1) "filename.txt"
2) "filename2.txt"
3) "file
4) name3.txt"

It completely ignores quotes. How to make it work with quotes?

Answer 1

Hard without seeing what you're using or any code. Your shell may be interfering, you may need to escape the spaces with \\ .

Example: python script.py -oa -f "file1.txt" "file\\ 2.csv"

Answer 2

Is hard without code but considering you are using sys.argv[] you can easily pass the file arguments with quotes like when you need a file or argv with blank spaces: python script.py "myFile.txt" "otherFile.jpeg" Try this simple code to understand:

import sys

for n, p in enumerate(sys.argv):
    print("Parameter: %d = %s") % (n, p))`

You can see that first argv is the file name you are running.

Answer 3

It looks like that this is not python's fault. I'm calling python script from inside of bash script and this make mess with quotes as parameters.