how to retrieve same column data and display as group

Question

a table named users_log contains users login and logout time and date, but i am not able to sort data as i intend.

Query

mysql_query('SELECT * FROM users_log WHERE u_id = 52 ORDER BY date_log')

It sort data like

Fri 12 Jul 13 - 03:41:40 PM - 03:42:31 PM

Fri 12 Jul 13 - 05:35:40 PM - 05:42:31 PM

Sat 13 Jul 13 - 02:29:09 PM - 02:34:52 PM

users_log table

log_id, u_id,  date_log,   logged_date,   login_time,   logout_time

2,      52,   2013-01-12, Fri 12 Jul 13,  03:41:40 PM,  03:42:31 PM

as i intend to display data

         Fri 12 Jul 13
   03:41:40 PM - 03:42:31 PM
   05:35:40 PM - 05:42:31 PM
         Sat 13 Jul 13
   02:29:09 PM - 02:34:52 PM

Answer 1

Do this:

$result = mysql_query('SELECT * FROM users_log WHERE u_id = 52 ORDER BY date_log');
$sorting = array();
while($row = mysql_fetch_assoc($result))
{
    $sorting[$row['logged_date']][] = $row['login_time']."-".$row['logout_time'];
}

//Now you loop over the sorted data using foreach($sorting as $key => $value) and display it any way you want.

I hope this can be of some help.

Answer 2

IMHO you should do something like(i assume you want to do it in php):

SELECT date_log FROM users_log WHERE u_id = 52 GROUP BY date_log,

then iterate over results (in php) and get the corresponding rows for date:

SELECT * FROM users_log WHERE u_id = 52 AND date_log = $date_for_current_iteration ORDER BY date_log;