i need regular expression
for number started with 0 and the length of this number is 11
i find this regular expression for numbers but this is not for length and 0 at started
$('#myModal #transfer_charge_model_mob').keyup(function () {
var inputVal = $(this).val();
var numericReg = /^\d*[0-9](|.\d*[0-9]|,\d*[0-9])?$/;
if (!numericReg.test(inputVal)) {
$('#myModal #transfer_charge_model_mob_lbl').text('please enter number');
$(this).val('');
}
else {
$('#myModal #transfer_charge_model_mob_lbl').text('');
}
});
You can do this without regex.
var x = $(this).val();
var y = x * 1;
if(!isNaN(y))
if (x.charAt(0) === '0' && x.length == 11)
//do whatever
You've overcomplicated your regex:
^0\d{10}$
is sufficent.
Converting my comment to an answer, seeing how popular it was
Note the on("change") rather than the keyup
$('#transfer_charge_model_mob').on("change",function () {
var inputVal = $(this).val();
var txt = /^0\d{10}$/.test(inputVal)?"":'please enter number';
$('#transfer_charge_model_mob_lbl').text(txt);
if (txt) $(this).val('');
});
For Keyup you might try
$(function() {
$('#transfer_charge_model_mob')
.on("change",function () {
var inputVal = $(this).val();
var txt = /^0\d{10}$/.test(inputVal)?"":'please enter number';
$('#transfer_charge_model_mob_lbl').text(txt);
//if (txt) $(this).val(''); // Very harsh if a typo
})
.on("keyup",function(e) {
var val = $(this).val();
var reg = /[^0-9]/g;
if (val.match(reg)) {
$(this).val(val.replace(reg,""));
}
});
});
var reg = /^0\d{10}$/;
console.log(reg.test("01111111111"));
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