I would like to use an array i made to run .superslides function on
$(function() {
$('#slides-1, #slides-2').superslides({
hashchange: false
});
});
here it is with the array i want to use
$(function() {
$(slideShowArr).superslides({
hashchange: false
});
});
and, just in case, here is how the array was made
$(".slideshow").each(function(i, el){
el.id = 'slides-' + (i + 1);
slideShowArr.push('#' + $(this).attr('id'));
});
so i need to pass slide show id's to .superslides function
Use the join
method of Array class to achieve this.
$(function() {
$(slideShowArr.join(",")).superslides({
hashchange: false
});
});
Not sure whether you really want this:
$(function() {
var slideShowArr = [];
$(".slideshow").each(function(i, el){
el.id = 'slides-' + (i + 1);
slideShowArr.push('#' + $(this).attr('id'));
});
$(slideShowArr.join(", ")).superslides({
hashchange: false
});
});
because it makes absolutely no sense to iterate over a collection giving each item an id and then making a new selection from all the generated ids - just use the collection you already have! Better:
$(function() {
$(".slideshow").prop("id", function(i) {
return 'slides-' + (i + 1);
}).superslides({
hashchange: false
});
});
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