I'm trying to extract a specific file from a zip archive using python.
In this case, extract an apk's icon from the apk itself.
I am currently using
with zipfile.ZipFile('/path/to/my_file.apk') as z:
# extract /res/drawable/icon.png from apk to /temp/...
z.extract('/res/drawable/icon.png', 'temp/')
which does work, in my script directory it's creating temp/res/drawable/icon.png
which is temp plus the same path as the file is inside the apk.
What I actually want is to end up with temp/icon.png
.
Is there any way of doing this directly with a zip command, or do I need to extract, then move the file, then remove the directories manually?
You can use zipfile.ZipFile.open :
import shutil
import zipfile
with zipfile.ZipFile('/path/to/my_file.apk') as z:
with z.open('/res/drawable/icon.png') as zf, open('temp/icon.png', 'wb') as f:
shutil.copyfileobj(zf, f)
Or use zipfile.ZipFile.read :
import zipfile
with zipfile.ZipFile('/path/to/my_file.apk') as z:
with open('temp/icon.png', 'wb') as f:
f.write(z.read('/res/drawable/icon.png'))
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.