Extract from directory inside zip file

Question

My existing code (a section) is loacted at the bottom of this post.

What I would like to do is extract all of the files from a directory inside of a zip file. Not the whole contents of a zip file, just the files in a directory ( /theme_files/ ) that's inside of a zip. I have already imported the neccesary libraries.

Extract the files from [filename].tpk/theme_files into ./workspace/[output]/

( .tpk = .zip )

theme_zip = zipfile.ZipFile(current_dir + "/themes/" + theme_name + ".tpk", 'r')
theme_zip.extractall(output_dir)
theme_zip.close()

Answer 1

for item in (f for f in theme_zip.filelist if 'theme_files/' in f.filename):
    theme_zip.extract(item, output_dir)

Answer 2

You could use ZipFile.extractall() and set the path and members args using a list comprehension on the filenames returned from ZipFile.namelist() :

import zipfile 

output_dir = './workspace/[output]/'
file = current_dir + "/themes/" + theme_name + ".tpk"

with zipfile.ZipFile(file, 'r') as f:
    files = [n for n in f.namelist() 
                   if n.startswith('/theme_files/') and not n.endswith('/')]
    f.extractall(path=output_dir , members=files)

Answer 3

Search the file names in the specific subfolders with regex. + Extract them file by file:

with open('<file-name>.zip', 'rb') as f:
    zf = zipfile.ZipFile(f)
    for file in [m.group() for m in (re.search(r'/theme/(.+)', file) for file in file_list) if m]:
        zf.extract(file)