Unable to scan all the elements of the string array using scanner in java

Question

I am unable to scan all the elements of the string array in Java. I don't know what is the error.. please help

I'm unable to scan the first element of the array.its not even showing an error.

import java.util.*;

public class uhu {

public static void main(String[] args) {

    System.out.println("Hit n");
    Scanner sc = new Scanner(System.in);
    try {
        int n = sc.nextInt();//scan the size of the array
        String[] str=new String[n];
        System.out.println("Enter elements");
        for (int i = 1; i < n; i++) //scanning the elements 
        {
            str[i]=sc.nextLine();
        }
        for (int i = 0; i < n; i++) //printing all the elements
        {
            System.out.println(str[i]);
        }
    } finally {
        if (sc != null)
            sc.close();
    }

}

}

Answer 1

Here you go :

System.out.println("Enter elements");
for (int i = 0; i < n; i++) //scanning the elements 
{
    str[i]= sc.next();
}

start from i=0 and use next() instead of nextLine().

In case you want to read whole lines then a BufferedReader will do the job, here in our case Scanner nextLine() is skipping the last line or taking a blank line as input at the end.

Use BufferedReader to get your job done.

System.out.println("Hit n");
BufferedReader buf = new BufferedReader(new InputStreamReader(System.in));
try {
    int n = Integer.parseInt(buf.readLine());//scan the size of the array
    String[] str=new String[n];
    System.out.println("Enter elements");
    for (int i = 0; i < n; i++) //scanning the elements 
    {
        str[i]= buf.readLine();
    }
    for (int i = 0; i < n; i++) //printing all the elements
    {
        System.out.println(str[i]);
    }
} catch (IOException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
} finally {
    if (buf != null)
        buf.close();
}