I need to cut out and save/use part of a string in C#. I figure the best way to do this is by using Regex. My string looks like this:
"changed from 1 to 10"
.
I need a way to cut out the two numbers and use them elsewhere. What's a good way to do this?
Error checking left as an exercise...
Regex regex = new Regex( @"\d+" );
MatchCollection matches = regex.Matches( "changed from 1 to 10" );
int num1 = int.Parse( matches[0].Value );
int num2 = int.Parse( matches[1].Value );
Matching only exactly the string "changed from x to y":
string pattern = @"^changed from ([0-9]+) to ([0-9]+)$";
Regex r = new Regex(pattern);
Match m = r.match(text);
if (m.Success) {
Group g = m.Groups[0];
CaptureCollection cc = g.Captures;
int from = Convert.ToInt32(cc[0]);
int to = Convert.ToInt32(cc[1]);
// Do stuff
} else {
// Error, regex did not match
}
In your regex put the fields you want to record in parentheses, and then use the Match.Captures
property to extract the matched fields.
There's a C# example here .
Use named capture groups.
Regex r = new Regex("*(?<FirstNumber>[0-9]{1,2})*(?<SecondNumber>[0-9]{1,2})*");
string input = "changed from 1 to 10";
string firstNumber = "";
string secondNumber = "";
MatchCollection joinMatches = regex.Matches(input);
foreach (Match m in joinMatches)
{
firstNumber= m.Groups["FirstNumber"].Value;
secondNumber= m.Groups["SecondNumber"].Value;
}
Get Expresson to help you out, it has an export to C# option.
DISCLAIMER: Regex is probably not right (my copy of expresso expired :D)
Here is a code snippet that does almost what I wanted:
using System.Text.RegularExpressions;
string text = "changed from 1 to 10";
string pattern = @"\b(?<digit>\d+)\b";
Regex r = new Regex(pattern);
MatchCollection mc = r.Matches(text);
foreach (Match m in mc) {
CaptureCollection cc = m.Groups["digit"].Captures;
foreach (Capture c in cc){
Console.WriteLine((Convert.ToInt32(c.Value)));
}
}
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