My script should be called like thiks:
# python start.py --config=start.cfg
So I've got three files:
start.py
import argparse
import options
parser = argparse.ArgumentParser(prog='mystart')
parser.add_argument("-f", "--file", dest="filename",
help="write report to FILE", metavar="FILE")
args = parser.parse_args()
ConfigFile = args.filename
test = options.getTest()
print test
options.py
from ConfigReader import getConfigValue as getVal
def getTest():
Test = getVal('main', 'test')
return Test
ConfigReader.py
import os
import ConfigParser
def config():
cfg = ConfigParser.ConfigParser()
for f in ('default.cfg',):
if os.path.exists(f):
cfg.read(f)
return cfg
return None
def getConfigValue(Section, Option):
cfg = config()
if cfg.has_option(Section, Option):
return cfg.get(Section, Option)
else:
return None
As you can see my config file is hard coded in my module ConfigReader.py. How can I pass now my var ConfigFile into my module?
This is just a simple example. I have a hole bunch of files which should access this variable also.
Is a global variable an option? Is there another way?
start.py
...
options.ConfigFile = args.filename
...
options.py
from ConfigReader import getConfigValue as getVal, ConfigFile
def getTest():
Test = getVal('main', 'test')
return Test
ConfigReader.py
import os
import ConfigParser
ConfigFile='default.cfg'
def config():
cfg = ConfigParser.ConfigParser()
for f in set(['default.cfg',ConfigFile]):
if os.path.exists(f):
cfg.read(f)
return cfg
return None
def getConfigValue(Section, Option):
cfg = config()
if cfg.has_option(Section, Option):
return cfg.get(Section, Option)
else:
return None
I found a solution for me.
start.py
[...]
import ConfigRader
[...]
ConfigReader.LoadConfigFile(args.filename)
ConfigReader.py
[...]
_ConfigFile = None
def LoadConfigFile(File):
if not File:
File = 'default.cfg'
global _ConfigFile
_ConfigFile = File
[...]
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.