I am new in java. I am getting java Stack overflow Exception in regex strHindiText. What should I do for that?
try {
// This regex convert the pattern "{\fldrslt {\fcs1 \ab\af24 \fcs0 ऩ}{"
// into "{\fldrslt {\fcs1 \ab\af24 \fcs0 ऩ}}}{"
// strHindiText = strHindiText.replaceAll("\\{(\\\\fldrslt[ ])\\{((\\\\\\S+[ ])+)((\\s*&#\\d+;\\s*(-|,|/|\\(|\\)|\"|;|\\.|'|<|>|:|\\?)*)+)\\}\\{","{$1{$2$4}}}{");
// This regex convert the pattern "{\fcs0 \af0 ऩ{ or {\fcs0 \af0 *\tab ऩ{"
// into "{\fcs0 \af0 ऩ }{"
strHindiText = strHindiText.replaceAll("\\{\\s*((\\\\\\S+[ ](\\*)?)+\\s*)(-|,|/|\\(|\\)|\"|;|\\.|'|<|>|:|\\?)*[ ]*(((&#\\d+;)[ ]*(-|,|/|\\(|\\)|\"|;|\\.|'|<|>|:|\\?)*[ ]*)+)\\{", "{$1 $4$5 }{");
// This regex convert the pattern "{ऩ \fcs0 \af0 {"
// into "{ऩ \fcs0 \af0 }{"
strHindiText = strHindiText.replaceAll("\\{\\s*(((&#\\d+;)[ ]*(-|,|/|\\(|\\)|\"|;|\\.|'|<|>|:|\\?)*[ ]*)+)[ ]*((\\\\\\S+[ ])+)\\{", "{$1 $5 }{");
} catch(StackOverflowError er) {
System.out.println("Third try Block StackOverflowError in regex pattern to reform the rtf tags................");
er.printStackTrace();
// throw er;
}
Whenever these strHindiText contain large data it gives an java stackoverflow exception:
java.lang.StackOverflowError
2013-08-08 15:35:07,743 ERROR [STDERR] (http-127.0.0.1-80-9) at java.util.regex.Pattern$Curly.match0(Pattern.java:3754)
2013-08-08 15:35:07,743 ERROR [STDERR] (http-127.0.0.1-80-9) at java.util.regex.Pattern$Curly.match(Pattern.java:3744)
2013-08-08 15:35:07,744 ERROR [STDERR] (http-127.0.0.1-80-9) at java.util.regex.Pattern$GroupTail.match(Pattern.java:4227)
2013-08-08 15:35:07,744 ERROR [STDERR] (http-127.0.0.1-80-9) at java.util.regex.Pattern$BmpCharProperty.match(Pattern.java:3366)
2013-08-08 15:35:07,745 ERROR [STDERR] (http-127.0.0.1-80-9) at java.util.regex.Pattern$Curly.match0(Pattern.java:3782)
2013-08-08 15:35:07,745 ERROR [STDERR] (http-127.0.0.1-80-9) at java.util.regex.Pattern$Curly.match(Pattern.java:3744)
My strHindiText data is:
`{\rtlch\fcs1 \af1\afs18 \ltrch\fcs0 \f1\fs18\cf21\insrsid13505584 भोपाल  । \par }\pard\plain \ltrpar\s16\ql \li0\ri0\sb100\sa100\sbauto1\saauto1\sl240\slmult0\widctlpar\wrapdefault\aspalpha\aspnum\faauto\adjustright\rin0\lin0\itap0\pararsid13505584 \cbpat20 \rtlch\fcs1 \af0\afs24\alang1025 \ltrch\fcs0 \fs24\lang1033\langfe1033\cgrid\langnp1033\langfenp1033 {\rtlch\fcs1 \ab\af1\afs18 \ltrch\fcs0 \cs21\b\f1\fs18\cf21\insrsid13505584 अन्वेषण करें  :}{\rtlch\fcs1 \af1\afs18 \ltrch\fcs0 \f1\fs18\cf21\insrsid13505584 \par भोपाल , मध्य प्रदेश की राजधानी प्राकृतिक सुंद`
Look for recursive calls in your regex.
If you are not sure where your problem lies: try a regex tester like this .
Don't use a regex if there are better tools for your task.
In your case you could: Search for a RTF parsing library or write your own parser.
eg like the one here that jahroy pointed out in the comments.
This is not a full answer but just for your information.
In your regex:
(-|,|/|\\\\(|\\\\)|\\"|;|\\\\.|'|<|>|:|\\\\?)*
can be written as [-,/()\\";.'<>:?]*
Since this pattern occurs twice (in your first regex), this immediately shortens your regex by 40 characters and makes those sections much more readable.
Try this to catch the error
public class Example {
public static void endless() {
endless();
}
public static void main(String args[]) {
try {
endless();
} catch(StackOverflowError t) {
// more general: catch(Error t)
// anything: catch(Throwable t)
System.out.println("Caught "+t);
t.printStackTrace();
}
System.out.println("After the error...");
}
}
More importantly try increasing the size of the stack add this to your regex
+'xss='xss
adding the "+" symbol changes the operator to prevent back tracking since this doesnt seem to be necessary in your case.
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