Arrange List<> in ascending order

Question

我有一个列表，其类型是字符串，我想按升序排列

listCustomFields = new List<String>() { "FirstName", "MiddleName", "Class" };

Answer 1

You can use LINQ OrderBy method (it will generate new List<string> with items sorted):

var ordered = listCustomField.OrderBy(x => x).ToList();

or List<T>.Sort method (it will sort the list in place):

listCustomField.Sort();

Answer 2

用这个

listCustomFields.sort();

Answer 3

You can use OrderBy like;

Sorts the elements of a sequence in ascending order.

listCustomFields = listCustomFields.OrderBy(n => n).ToList();

As an alternative, you can use List<T>.Sort Method also.

List<String> listCustomFields = new List<String>() { "FirstName", "MiddleName", "Class" };
listCustomFields = listCustomFields.OrderBy(n => n).ToList();

foreach (var item in listCustomFields)
{
   Console.WriteLine(item);
}

Output will be;

Class
FirstName
MiddleName

Here a DEMO .

Answer 4

You do not need LINQ for that: rather than creating a sorted copy, you can sort your list in place by calling Sort() method on it:

listCustomFields.Sort();

The order is implicitly ascending. If you need to change that, supply a custom comparer.