I have a program like this,
BigDecimal bd = new BigDecimal(23.086);
BigDecimal bd1= new BigDecimal(0.000);
bd = bd.setScale(2, RoundingMode.HALF_UP).stripTrailingZeros();
bd1 = bd1.setScale(2, RoundingMode.HALF_UP).stripTrailingZeros();
System.out.println("bd value::"+ bd);
System.out.println("bd1 value::"+ bd1);
I get the following output: 23.09
for bd
and 0.00 for bd1
, but I want bd1
as 0
not as 0.00
. Am I applying the methods correctly?
try this
import java.math.BigDecimal;
import java.text.DecimalFormat;
public class calculator{
public static void main(String[] args) {
BigDecimal bd = new BigDecimal(23.086);
BigDecimal bd1= new BigDecimal(0.000);
DecimalFormat df = new DecimalFormat("0.##");
System.out.println("bd value::"+ df.format(bd));
System.out.println("bd1 value::"+ df.format(bd1));
}
}
Simple, clean, flexible, easy-2-understand and maintain code
( will work for double
too )
DecimalFormat df = new DecimalFormat();
df.setMaximumFractionDigits(2); //Sets the maximum number of digits after the decimal point
df.setMinimumFractionDigits(0); //Sets the minimum number of digits after the decimal point
df.setGroupingUsed(false); //If false thousands separator such ad 1,000 wont work so it will display 1000
String result = df.format(bd);
System.out.println(result);
BigDecimal bd = new BigDecimal(23.086);
BigDecimal bd1 = new BigDecimal(0.000);
bd = bd.setScale(2, RoundingMode.HALF_UP).stripTrailingZeros();
bd1 = bd1.setScale(2, RoundingMode.HALF_UP).stripTrailingZeros();
System.out.println("bd value::"+ bd); System.out.println("bd1 value::"+ bd1);
System.out.println("new way:" + bd1.intValueExact());
//OUTPUT bd value::23.09
bd1 value::0.00
new way:0
You can use printf()
-- the %f
specifier works for BigDecimal
s too:
System.out.printf("bd1 value::%.0f%n", bd1);
bd1 value::0
Let's say you have BigDecimal with value 23000.00
and you want it to be 23000
. You can use method stripTrailingZeros()
, but it will give you "wrong" result:
BigDecimal bd = new BigDecimal("23000.00");
bd.stripTrailingZeros() // Result is 2.3E+4
You can fix it by calling .toPlainString()
and passing this to the BigDecimal constructor to let it handle correctly:
BigDecimal bd = new BigDecimal("23000.00");
new BigDecimal(bd.stripTrailingZeros().toPlainString()) // Result is 23000
你可以这样做
System.out.println("bd value: " + ((bd.scale() == 0) ? bd.unscaledValue() : bd));
This method below works better IMO
bd1 = bd1.stripTrailingZeros();
System.out.println(bd1.toPlainString());
Prints:
0
If bd1 = 1.2300 , this will print
1.23
i create this method to fix my problem...
private BigDecimal removeZeros(BigDecimal bigDecimal){
return new BigDecimal(bigDecimal.stripTrailingZeros().toPlainString());
}
i don't like it, but do the job
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