I am testing a program midway through, and noticed that printf is displaying some of my stored values as 0's. Particularly when I try to, using printf, display them in one command. They work fine individually, I have checked this. Here's my code:
#include <math.h>
#include <stdio.h>
#include <stdlib.h>
/* Initialization of variables */
double int1;
double int2;
double int3;
double int4;
double int5;
/* Initialization of calculated values */
double a_mean;
double g_mean;
double h_mean;
double st_dev;
n = 5; /* Total number of integers for summation use */
int main()
{
printf("Enter 5 integers, pressing 'Enter' after each:\n"); /* Prompts user input */
/* Scans in entered integer values (5) */
scanf("%d", &int1);
scanf("%d", &int2);
scanf("%d", &int3);
scanf("%d", &int4);
scanf("%d", &int5);
/* Calculations */
/* Output */
printf("The five integers entered were:\n");
printf("%d, %d, %d, %d, and %d", int1, int2, int3, int4, int5);
return 0;
}
Enter 5 integers, pressing 'Enter' after each: 1 2 3 4 5
The five integers entered were: 1, 0, 2, 0, and 3
By the way, ignore the missing /* Calculations */ section in the middle, I am just testing my current progress... But see how I entered 1,2,3,4,5 and only some values print correctly? On individual printf lines they work. What am I doing wrong??
Though you names these variables int1
etc, their type is double
! So either declare them as int
or if you choose to use double
:
Change
scanf("%d", &int1);
to
scanf("%lf", &int1);
and give them better names.
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