Parse date time with PM/AM

Question

I want to parse the following date-time format:

8/1/2013 3:52:05 PM

What should I use for format ?

DateTime.ParseExact("8/1/2013 3:52:05 PM", "format", CultureInfo.InvariantCulture);

Answer 1

"tt" - The AM/PM designator.

So your format string should be: M/d/yyyy h:mm:ss tt

Console.WriteLine(DateTime.ParseExact("8/1/2013 3:52:05 PM", "M/d/yyyy h:mm:ss tt", CultureInfo.InvariantCulture));

prints 2013-08-01 15:52:05

But, you can easily do the same without specifying the format:

DateTime.Parse("8/1/2013 3:52:05 PM", CultureInfo.GetCultureInfo("en-us"))

Works just fine. Your input is formatted using en-US format.

Answer 2

DateTime date = DateTime.ParseExact("8/1/2013 3:52:05 PM", "d/M/yyyy h:mm:ss tt", CultureInfo.InvariantCulture);
Console.WriteLine(date);

Output will be;

1/8/2013 3:52:05 PM

Here a DEMO .

Further reading;