I have some nested code and I want to check it's condition and print the statement once. But I don't know how to reform the for loop or which is the ideal loop for this situstin to use.? I have written this and I am getting hello printed 4 times..I want it to be printed once.. Please help.
countDev = dev.findElements(
By.xpath("html/body/form/div[2]/div[2]/ul/li")).size();
countProd = prod.findElements(
By.xpath("html/body/form/div[2]/div[2]/ul/li")).size();
System.out.println(countDev);
System.out.println(countProd);
if (countDev == countProd) {
for (int list = 1; list <= countDev; list++) {
if (dev.findElement(
By.xpath("/html/body/form/div[2]/div[2]/ul/li[" + list
+ "]/a/span"))
.getText()
.equals(prod.findElement(
By.xpath("/html/body/form/div[2]/div[2]/ul/li["
+ list + "]/a/span")).getText())) {
}
System.out.println("Hello!");
}
} else {
System.out.println("Bye, Bye!");
}
Not sure what you are trying to achieve, But just put a flag there and make it as true once print done.
boolean printed =false;
for (int list = 1; list <= countDev; list++) {
if (your condtion here ) {
if(!printed ){
System.out.println("Hello!");
printed = true;
}
}
}
This loop will execute four times if countDev and countProd are equal to 4
for (int list = 1; list <= countDev; list++)
Also, your if statement is empty and your 'Hello' print statement is outside the if but inside the loop
Hlo. Buddy..I can't understood you clearly... try this code..
countDev = dev.findElements(
By.xpath("html/body/form/div[2]/div[2]/ul/li")).size();
countProd = prod.findElements(
By.xpath("html/body/form/div[2]/div[2]/ul/li")).size();
System.out.println(countDev);
System.out.println(countProd);
if (countDev == countProd) {
for (int list = 1; list <= countDev; list++) {
if (dev.findElement(
By.xpath("/html/body/form/div[2]/div[2]/ul/li[" + list
+ "]/a/span"))
.getText()
.equals(prod.findElement(
By.xpath("/html/body/form/div[2]/div[2]/ul/li["
+ list + "]/a/span")).getText())) {
System.out.println("Hello!");
break;
}
}
} else {
System.out.println("Bye, Bye!");
}
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