I have strings of the following form in C++
string variable1="This is stackoverflow \"Here we go "1234" \u1234 ABC";
Now in this string I want to delete all characters except alphabets(From a to b, and A to B) and numbers. So that my output becomes
variable1="This is stackoverflow Here we go 1234 u1234 ABC";
I tried to check for each and every character using pointers but found it very inefficient. Is there an efficient way to achieve the same using C++/C?
Use std::remove_if
:
#include <algorithm>
#include <cctype>
variable1.erase(
std::remove_if(
variable1.begin(),
variable1.end(),
[] (char c) { return !std::isalnum(c) && !std::isspace(c); }
),
variable1.end()
);
Note that the behaviors of std::isalnum
and std::isspace
depend on the current locale.
working code example: http://ideone.com/5jxPR5
bool predicate(char ch)
{
return !std::isalnum(ch);
}
int main() {
// your code goes here
std::string str = "This is stackoverflow Here we go1234 1234 ABC";
str.erase(std::remove_if(str.begin(), str.end(), predicate), str.end());
cout<<str;
return 0;
}
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