I want to do the following code, which is what BS documentation says to do, the only problem is that the word "class" isn't just a word. It can be found inside HTML, but it's also a python keyword which causes this code to throw an error.
So how do I do the following?
soup.findAll('ul', class="score")
Your problem seems to be that you expect find_all
in the soup to find an exact match for your string. In fact :
When you search for a tag that matches a certain CSS class, you're matching against any of its CSS classes:
You can properly search for a class tag as @alKid said. You can also search with the class_
keyword arg.
soup.find_all('ul', class_="score")
这是如何做到的:
soup.find_all('ul', {'class':"score"})
If OP is interested in getting the finalScore
by going through ul
you could solve this with a couple of lines of gazpacho :
from gazpacho import Soup
html = """\
<div>
<ul class="score header" id="400488971-linescoreHeader" style="display: block">
<li>1</li>
<li>2</li>
<li>3</li>
<li>4</li>
<li id="400488971-lshot"> </li>
<li class="finalScore">T</li>
</ul>
<div>
"""
soup = Soup(html)
soup.find("ul", {"class": "score"}).find("li", {"class": "finalScore"}).text
Which would output:
'T'
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