Running a Java Application from the Windows Context Menu

Question

I would like to create a Java application that can be opened from the context menu of any given file or directory on the computer. I know how to add my program to the registry so that it appears when right-clicking on a file, but how can I receive the location of the directory/file from which my program was run in order to work with it inside the application?

Is there a way that I can receive it as an argument in the main?

Answer 1

First convert your jar to exe file. then you add to registry and whatever.. if you set whenever you open with right click on file ( you must set the file association, that is your application. Ex: Right click on your targeted file select open with and select your application ) your application main function receive the path in args[0]. that's all...

Answer 2

Add the context menu. Tell it to run CMD. Tell CMD to run the jar (and then close).

HKEY_CLASSES_ROOT\ * \shell\ClickMe\Command
default="cmd \\c java c:\myJar.jar \"%1\""