Python regex to match string

Question

I'm new here. Just having a problem with Python regex. I have a strings like

http://sample.com/test/id549268848?at=5
http://sample.com/test/id621311331?at=5
...

Can't find the right way to get only number after id and strip everything after. Calling from the loop like this

self.splitAppId(rec[4])

Where rec[4] URL from list

The function itself:

def splitAppId(self, url):
        idMatch = re.search('/id(.*)?$', url)
        return idMatch

Answer 1

you doing wrong. Should be like this:

 def splitAppId(self, url):
        idMatch = re.search(r'/id([^/]+)\?[^/]*$', url)
        return idMatch.group(1)

Answer 2

If URL is format, then

>>> "http://sample.com/test/id549268848?at=5".split('id')[-1].split('?')[0]
'549268848'