get pid of process - linux

Question

I try to launch an app within it's path and get it's process id:

(cd /opt/server/TrackServer/release && ./TrackServer&) && echo $!

but I always get wrong PID.

Ie i get:

$ (cd /opt/server/TrackServer/release && ./TrackServer&) && echo $!
5078
$ ps aux | grep TrackServer
user    5250  0.6  0.0 153340  7824 pts/0    S    20:09   0:00 ./TrackServer
user    5253  0.0  0.0  14868   976 pts/0    S+   20:09   0:00 grep --color=auto TrackServer

how can I invoke the process within its path and get it's pid?

Answer 1

如果只有一个正在运行，使用pidof TrackServer

Answer 2

TrackServer is a background process of the (...) -induced subshell, not your script, so $! in your script stores a different PID.

Try

pushd /opt/server/TrackServer/release && { ./TrackServer & echo $!; popd; }