Regex - Find from second occurrence till second last occurrence

Question

I'm trying to match everything between first and last occurrence with Javascript's .match() or .replace() function. I will therefore be using regex to find what I need to remove. Content will be different with many lines and other characters, but this is just an example.

[quote=Person 1]
[quote=Person 2]
[quote=Person 3]
Person 3
[/quote]
Person 2
[/quote]
Person 1
[/quote]

I need to match and remove everything from second occurrence [quote=Person 2] till second last [/quote]

With that said, it should output this in the end:

[quote=Person 1]
Person 1
[/quote]

You can match the quote tags like this

\[quote(.*?)\] 

and the end quote tag like this

\[\/quote\]

Answer 1

Here you go (where x is the above example text):

var newx = x.replace(/^(\[quote=(?:(?!\[quote=)[\s\S]*?))\[quote=[\s\S]+\[\/quote\]\s*([\s\S]+?\[\/quote\]\s*)$/g, "$1$2")

This produces:

[quote=Person 1]
Person 1
[/quote]

Note that x.replace() doesn't change the contents of x -- you have to do an assignment like var newx = x.replace(...); or x = x.replace(...) to store the modified string.

Answer 2

使用此模式(\\[quote=([^\\]]+)\\])[\\s\\S]+(?=\\s\\2)并替换为$1 演示