keep original index of array (continued)

Question

Hey guys thanks for your help previously especially to Sam I am, almost got this working however due to an family emergency had to stop working on it for a while, everything seems to be working except one bit which is keeping the original indicies:

int [] indices = new int [15];         
for(int i=0; i<indices.length; i++){indices[i] = i;} 

// Below code used for sorting
for (int i=0; i<distances.length; i++)
{
for(int j = i+1; j<distances.length; j++)
{
    if (distances[i] > distances[j])  
    {
         double temp = distances[j];
        distances[j] = distances[i];
        distances[i] = temp;                                      

         int tempindex = indices[i];
         indices[j] = indices[i];
         indices[i] = tempindex;                                       
    }            
 }       
 }

for (int i=1; i<distances.length; i++) 
{
 System.out.println("Point "+indices[i] + " -> " + distances[i]);
}

}

Sam I am did explain how to do it however seem to be having trouble getting the code to display the original index so does anyone have any ideas?

Answer 1

Don't know if I've understood your question. But I think there is an idex problem.

Thake a loot to the index you use when you assign tempindex.

int tempindex = indices[i];
indices[j] = indices[i];
// tempindex is equal to indeices[i], so this instruction does nothing.
indices[i] = tempindex; 

Try to change

int tempindex = indices[i];

To

int tempindex = indices[j];