I have a translation engine api made using Django Python and it has a function that I want to be made into a class based view:
def i18n_newkey(rin):
request = Request(rin, JSONParser())
if request.method == 'POST':
data = json.loads(rin.body)
.... # Parsing and other code here and finally,
return JSONResponse(kdata)
Where the JSONResponse is an HttpResponse that renders it's content into JSON.
My url: url(r'^savekey', 'i18n_newkey'),
I'm new to django and I wanted to convert my function based view to class view, I've read the Django Documentation but I cannot seemed to dig it in this particular code.
Thanks!
似乎JsonRequestResponseMixin可以完全满足您的要求。
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