I have a Message struct, and a function that creates a new Message and does something with it.
type Message struct {
To string
From string
Body string
}
func Message() {
newMessage := Message{Body: "test"}
// do something with newMessage
}
I'd like to pass the parameters to the struct into the function, kind of like this (obviously not syntactically correct, but you get the gist).
func Message(/*params*/) {
newMessage := Message{/*params*/}
// do something with newMessage
}
The problem is, struct parameters themselves don't have a type, so there's no way to give them directly to a function. I could probably give the function a map, and get the parameters out of there, but I want to keep using the message function as simple as possible, avoiding things like this:
Message(Message{/*params*/})
and
var params map[string]string
// set parameters
Message(params)
What exactly are you trying to accomplish? Why don't struct parameters themselves have a type. What is wrong with this?
package main
import "fmt"
type Message struct {
To string
From string
Body string
}
func NewMessage(to, from, body string) *Message {
message := &Message{
To: to,
From: from,
Body: body,
}
// do something with message
return message
}
func main() {
message := NewMessage(
"message to",
"message from",
"message body",
)
fmt.Println("Message: ", *message)
}
Output:
Message: {message to message from message body}
Just pass in a message directly:
func Send(msg Message) {
// do stuff with msg
}
Send(Message{"to","from","body"})
If there are additional properties you need to initialize you can do it like this:
type Message struct {
id int
To, From, Body string
}
func (this *Message) init() {
if this.id == 0 {
this.id = 1 // generate an id here somehow
}
}
func Send(msg Message) {
msg.init()
// do stuff with msg
}
Send(Message{
To: "to",
From: "from",
Body: "body",
})
Though it's hard to know the best approach without more information.
I think you want sth like this, but it's not valid style in Golang.
Message(To:'Ray',From:'Jack')
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