void foo(const C &);
foo(C());
In this case, temporary C
object lives until the end of foo()
.
But my question is:
struct C { operator int(); }
void bar(int i);
bar(C());
In that case, Does temporary C
object live until the end of bar()
? If not, Is there any way to make temporary object live until the end of bar()
?
edit: Thanks to user2109558, I know the code doesn't work. Then does the following code work well?
void bar(int i);
void bar(C &&c) { bar(c); }
No!the code bar(C());
is equal to int num = C(); bar(num);
int num = C(); bar(num);
So , temporary C object does not live until the end of bar() you have to change bar
function parameter.such as void bar(const C &)
or add global C object variable eg:
C c;
void bar(int i) {
.....
}
but no suggestion do it.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.