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BASH: AWK - find the smallest and largest number with condition “if”

原文 2014-02-12 10:32:48 4 1 bash/ if-statement/ awk/ conditional-statements/ min

I've got syntax problem with awk and I don't know how to fix it:

 awk -F: -v lim=100 '{if ($1 >= lim)} NR == 1 {line = $0; min = $1} NR > 1 && $1 < min {line = $0; min = $1} END {print min}' file.txt

I want to get printed the smallest number in $1 column but greater than 100. It's works fine but without condition "if".

1 answers

Try this awk:

awk -F: -v lim=100 '(!min || $1 < min) && $1 >= lim {min=$1} END{print min}' file.txt

If there is no number >= 100 then it will just print 0.

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