$name = array('maxgebruikers' => $_POST['maxgebruikers']);
$name1 = array('maxplaylist' => $_POST['maxplaylist']);
array_push($name,$name1);
$result = mysql_query("SELECT * FROM organisation_settings WHERE organisation_id = '{$organisatieID}'");
if(mysql_fetch_assoc($result) == 0)
{
foreach($name as $type=>$value) {
mysql_query("INSERT INTO organisation_settings (type, value, organisation_id)
VALUES('{$type}', '{$value}' ,'{$organisatieID}')");
print_r($name);
}
}
else
{
foreach($name as $type=>$value) {
mysql_query("UPDATE organisation_settings
WHERE organisation_id = '{$organisatieID}'(type, value, organisation_id)
SET VALUES('{$type}', '{$value}' ,'{$organisatieID}')");
print_r($name);
}
}
As you can see at the picture, I want where type is
like my array;
It won't insert correctly, where and what is the error in the code?
I know I should use mysqli function, but it is not the point now.
you need to use array like this,
$name = array('maxgebruikers' => $_POST['maxgebruikers'],
'maxplaylist' => $_POST['maxplaylist']
);
now you dont have to use array_push if you need you must create new array.
in your code you are changing $name with $name1 so it doesnt work, actually works..
You use array_push to add $name1 to $name. so your name array now looks like this:
$name = array('maxgebruikers' => $_POST['maxgebruikers'],
array('maxplaylist' => $_POST['maxplaylist']));
you have now got an array in your $name array. but when you call it you only call the second value of this $name array. after that you need to call the first value of the $name1 array within the $name array.
I hope you get what i mean.
This is because you put an array in an array. If you want to make it work you'll need te redifne your variables. See my PHPFiddle http://phpfiddle.org/main/code/zsw-jdj
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