java - regex for string between two characters

Question

How do I get the stuff in between two #? I have this

^(#(.+?)#)

and it returns a string

#blah blah blah#

but I only want

blah blah blah

How do I exclude the #?

Answer 1

您要查找的正则表达式为"#(.*?)# （请参见示例 ）。

Answer 2

There are two groups in this regex. The first group (the outer parentheses) will give you "#blah blah blah#", and the second group will give you what you are looking for, "blah blah blah". You should access match.group(2) for the required result, where match is the matcher object.

Answer 3

The basic idea is to exclude the '#' characters from the capture group. The following will capture the text between the '#' but not the '#' characters themselves:

#(.*)#

Now, what if there are no characters between the '#'? If the string is ## , the above expression will capture an empty string. That might be what you want. But you might want the capture to fail instead. The following will do that:

#(.+)#    // Force the captured string to be non-empty

Now, what if the string might contain more than two '#'? For example, if the string is #a#b# , do you want it to capture a#b or a ? The previous regexes would capture the longer string. If you want the shorter, then either of the following should do that:

#(.*?)#       // Like your original example
#([^#]*)#     // capture only sequences of non-# characters