how to find and replace [0-9]* inside a file, linux

Question

how can you find [0-9] as this is treated as a pattern by linux

Need to search for 10.179.[0-9]*.150 and replace it with 10.179.227.150 inside a file

Answer 1

sed 's/10\.179\.[0-9]*\.150/10.179.227.150/g' input.txt >output.txt

或者，如果您必须将[0-9]*视为文字字符串，而不是任何数字，请在上面将其转义为\\[0-9\\]\\* 。

Answer 2

If [0-9]* is a regex pattern:

sed -i s/10\.179\.[0-9]*\.150/10.179.227.150/g file.txt

If [0-9]* is to be taken literally:

sed -i s/10\.179\.\[0-9\]\*\.150/10.179.227.150/g file.txt