Converting int to a byte array

Question

Most bitshift solutions I have seen for converting an int to a byte array go like this:

return new byte [] {
    (byte) ((i >> 24) & 0xFF),
    (byte) ((i >> 16) & 0xFF),
    (byte) ((i >> 8) & 0xFF),
    (byte) (i & 0xFF);
}

Why the & 0xFF??

Answer 1

& 0xFF是冗余的，在给定情况下没有区别