I am on a Linux system and I am trying to rename all .jpg files in many subdirectories to sequential filenames, so all the jpeg files in each subdirectory are renamed 0001.jpg, 0002.jpg, etc. I have a 'rename' command that works in a single directory:
rename -n 's/.*/sprintf("%04d",$::iter++ +1).".jpg"/e' *.jpg
I am trying to use it like this:
for i in ls -D; do rename -n 's/.*/sprintf("%04d",$::iter++ +1).".jpg"/e' *.jpg; done
but for output I get this:
*.jpg renamed as 0001.jpg
for each subdirectory. What am I doing wrong?
You need to put the command in backticks (or use the $( ... )
bash syntax) in order to iterate over its output. Also use the $i
variable together with the *.jpg file name pattern, eg
for i in `ls -D`
do
rename -n 's/.*/sprintf("%04d",$::iter++ +1).".jpg"/e' $i/*.jpg
done
however, for this scenario you want to iterate over all the subdirectories, and you are better of using the find command:
for i in `find . -type d`; do rename ...
It seems to me you've forgot to change a current working directory so it should looks like
for i in *; do
[ -d "$i" ] || continue
pushd "$i"
# rename is here
popd
done
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