I have a series of files that I would like to clean up using commandline tools available on a *nix system. The existing files are named like so.
filecopy2.txt?filename=3
filecopy4.txt?filename=33
filecopy6.txt?filename=198
filecopy8.txt?filename=188
filecopy3.txt?filename=19
filecopy5.txt?filename=1
filecopy7.txt?filename=5555
I would like them to be renamed removing all characters after and including the "?".
filecopy2.txt
filecopy4.txt
filecopy6.txt
filecopy8.txt
filecopy3.txt
filecopy5.txt
filecopy7.txt
I believe the following regex will grab the bit I want to remove from the name,
\?(.*)
I just can't figure out how to accomplish this task beyond this.
If all files are in the same directory (ignoring .dotfiles
):
$ rename -n 's/\?filename=\d+$//' -- *
If you want to rename files recursively in a directory hierarchy:
$ find . -type f -exec rename -n 's/\?filename=\d+$//' {} +
Remove -n
option, to do the renaming.
find . -depth -name '*[?]*' -exec sh -c 'for i do
mv "$i" "${i%[?]*}"; done' sh {} +
With zsh
:
autoload zmv
zmv '(**/)(*)\?*' '$1$2'
Change it to:
zmv -Q '(**/)(*)\?*(D)' '$1$2'
if you want to rename dot files as well.
Note that if filenames may contain more than one ?
character, both will only trim from the rightmost one.
A bash command:
for file in *; do
mv $file ${file%%\?filename=*}
done
I this case you can use the cut command:
echo 'filecopy2.txt?filename=3' | cut -d? -f1
example:
find . -type f -name "*\?*" -exec sh -c 'mv $1 $(echo $1 | cut -d\? -f1)' mv {} \;
You can use rename if you have it:
rename 's/\?.*$//' *
I use this after downloading a bunch of files where the URL included parameters and those parameters ended up in the file name.
This is a Bash script.
for file in *; do
mv $file ${file%%\?*};
done
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