I am trying to compare the values of 2 data frame. If any of the values is different, I will return that row.
df1
Value1 Value2
Name
a 1 1
b 1 2
c 0 1
df2
Value Value2
Name
a 1 1
b 1 1
c 1 1
I did a df1==df2
df3
Value Value2
Name
a True True
b True False
c False True
I want to return only b and c, how can I do it? I do not want to do
df3[(df3['Value']==False)|(df3['Value2'==False)]
because I may have more than 2 columns and columns names can differ
Assuming you have a data file (d3.txt) or list of data like (line),
line = [i.strip().split() for i in open("d3.txt").readlines()]
print line
[['#df3'], ['#', 'Value', 'Value2'], ['#Name'], ['#a', 'True', 'True'], ['#b', 'True', 'False'], ['#c', 'False', 'True']]
for i in line[:][:]:
mydict[i[0]] = ",".join(li[li.index(i)][1:])
I just created a dictionary. So you can call
print mydict
print mydict['#a'] #Depend of which name you want to look.
The output is
{'#': 'Value,Value2', '#c': 'False,True', '#b': 'True,False', '#a': 'True,True', '#Name': '', '#df3': ''}
True,True
Or you can do this way without creating the dictionary,
for n in range(len(line)):
if (line[n][0] == '#c' or line[n][0]== '#b'):
print line[n][:]
And the output is (maybe this is what you want):
['#b', 'True', 'False']
['#c', 'False', 'True']
我认为这应该做到:
df3[~df3.all(axis=1)]
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