Ascending order Sorted array is getting printed in descending order?

Question

   public void sortcolumn(double[] arraytosort) {
    a = new int[5];
    for (int i = 1; i < arraytosort.length; i++) {
        for (int j = 1; j < arraytosort.length; j++) {
            if ((arraytosort[i]) > (arraytosort[j])) {
                tempVar = arraytosort[j];
                arraytosort[j] = arraytosort[i];
                arraytosort[i] = tempVar;
                a[i] = j;
              }
      }
 System.out.println( a[i]);
    }
}


public void decisionvalue(double[][] arraydc){
    arrtemp = new double[arraydc.length];
    for(int i =0; i<arraydc[0].length;i++){
        System.out.println("The column matrix is");
        for(int j =1; j<arraydc.length;j++){
            arrtemp[j] =  arraydc[j][i];
        System.out.println(arrtemp[j]);
      }
        sortcolumn(arrtemp);
         System.out.println("The sorted column matrix is" +i);
        for(int k =1; k<arraydc.length; k++)
     System.out.println(arrtemp[k]);  
          }
  }

By the code above I am sorting the columns of an array and then printing them. But I don't understand why the ascending order sorted elements are printed in descending order. Someone please check it. Thanks!!

Following is the output: This is the input matrix arraydc

0.0 0.0 0.0
25.0 10.0 24.0
25.0 5.0 23.0
25.0 23.0 6.0
25.0 89.0 8.0

---

The column matrix is 25.0 25.0 25.0 25.0

---

0 0 0 0

---

The sorted column matrix is0 25.0 25.0 25.0 25.0

---

The column matrix is 10.0 5.0 23.0 89.0

---

2 1 2 3

---

The sorted column matrix is1 89.0 23.0 10.0 5.0

---

The column matrix is 24.0 23.0 6.0 8.0

---

3 1 2 3

---

The sorted column matrix is2 24.0 23.0 8.0 6.0

---

Answer 1

for (int j = i; j < arraytosort.length; j++) {

从i开始第二个循环