regex match all numbers between []

Question

really simple regex question I have string that may look like:

• [10]
• [6378363]30
• []393

I'd like it so it would match 10, 6378363 and nothing respectively.

I tried something like (\\d+)[^]] (match 1 or more numbers as we know the first character will always be [) (up to ])

but this is just only matching numbers I am presuming I have the syntax for regex wrong as I am simply rubbish at regex! any help would be amazing

Answer 1

It should be like this:

\[(\d*)\]

The regex (\\d+)[^]] would match digits until a [ appears, so it won't capture digits between square brackets. [ and ] are special characters in regex, so they should be escaped with \\ .

>>> import re
>>> st = '[6378363]30'
>>> re.match('\[(\d*)\]', st).group(1)
'6378363'

Answer 2

You can use this one:

import re

input = '[10] [6378363]30 []393'
print re.findall('\[(\d+)\]', input)

\\d+ means one or more digits. This will ensure to avoid [] as it does have zero digits inside it.

Answer 3

您正在寻找的正则表达式是：

\[(\d*)\]