mysql select query only showing one data in php

Question

so I'm trying to show data from my sql table. There are two data but only one of them shows when I try to open my php page. here's my codes :

<?php
    include ("koneksi.php");

    // $username=$_GET['username'];
    $username="Dia";

    $result = mysql_query("SELECT * FROM tbl_penyakit_user WHERE username='Dia'");
    $row = mysql_fetch_array( $result );

    echo " penyakit: ".$row['penyakit'];

?>

I tried to run the select query on phpmyadmin an it showed 2 data. Thanks in advance

Answer 1

mysql_fetch_array only gets one array at a time. To properly get all available rows, put it in a while-loop like so:

while($row = mysql_fetch_array($result)) {
    echo " penyakit: " . $row['penyakit'];
}

As an aside, however, please note that the mysql_* functions are considered deprecated, and should not be used in future development. (Here's why )

Answer 2

You have to use while loop while more than one row.

<?php
    include ("koneksi.php");
    // $username=$_GET['username'];
    $username="Dia";

    $result = mysql_query("SELECT * FROM tbl_penyakit_user WHERE username='Dia'");
    while($row = mysql_fetch_array( $result ))
    {
        echo " penyakit: ".$row['penyakit'];
    }
?>

Answer 3

Try this:

$result = mysqli_query($con,"SELECT * tbl_penyakit_user WHERE username='Dia'");

    while($row = mysqli_fetch_array($result)) {
      echo $row['penyakit'];
    }

Hope this helps!

Answer 4

    <?php
 include ("koneksi.php");

// $username=$_GET['username'];
 $username="Dia";

 $result = mysql_query("SELECT * FROM tbl_penyakit_user WHERE username='Dia'");
 while($row = mysql_fetch_assoc( $result )){
     echo " penyakit: ".$row['penyakit'];
}

        ?>

Answer 5

You need to fetch each row so use a while loop

while ($row = mysql_fetch_array( $result )) {
    echo " penyakit: ".$row['penyakit'];
}

This should output all rows, you only fetch one.