What is the faster way to conver BigInteger to array of int?

Question

I have BigInt

BigInteger i = new BigInteger("5876934265987526278534978564378568734564937563487564327564376534875483753475");

I need to convert it to [] int . How can I do this fast?

My method is very slow

private static int[] convertDigitsToIntArray(java.math.BigInteger x) {
    String s = x.toString();
    int[] result = new int[s.length()];
    for (int i = 0; i < s.length(); i++) {
        result[i] = Integer.parseInt(String.valueOf(s.charAt(i)));
    }
    return result;
}

Answer 1

Convert it to a string and then iterate the characters:

int[] getArr(BigInteger num)
{
    String str = num.toString();
    int[] arr = new int[str.length()];
    for (int i=0; i<arr.length; i++)
         arr[i] = str.charAt(i)-'0';
    return arr;
}

Answer 2

May be this will help...

public static void main(String[] args) {
      BigInteger i = new BigInteger("5876934265987526278534978564378568734564937563487564327564376534875483753475");
      String iStr = i.toString();
      int[] intArray = new int[iStr.length()];
      for(int j=0; j<iStr.length(); j++) {
          intArray[j] = Integer.parseInt(String.valueOf(iStr.charAt(j)));
      }
  }

Answer 3

Try using this:

private static int[] convertDigitsToIntArray(java.math.BigInteger x) {
    String s = x.toString();
    int[] result = new int[s.length()];
    for (int i = 0; i < s.length(); i++) {
        result[i] = s.charAt(i) - '0';
    }
    return result;
}

Answer 4

You can convert the BigInteger to a String, get the char array of that string and iterate over that:

java.math.BigInteger source = new java.math.BigInteger("5876934265987526278534978564378568734564937563487564327564376534875483753475");

char[] array = source.toString().toCharArray();
int[] result = new int[array.length];
for(int i=0; i<array.length; i++)
{
    result[i] = array[i] - '0';
}