How to compress a specific file using pipeline in Django?

Question

I have many CSS files inside SITE_ROOT/sources/css and I want to compress only one file in SITE_ROOT/static/css using django-pipeline .

STATIC_ROOT = os.path.join(SITE_ROOT, 'static')

STATICFILES_DIRS = (
    os.path.join(SITE_ROOT, 'sources'),
)

PIPELINE_CSS = {
    'responsive': {
        'source_filenames': (
          'css/smartphones.css',
          'css/tablets.css',
        ),
        'output_filename': 'css/responsive.min.css',
    }
}

After running collectstatic I see in the static/ folder the minified file (responsive.min.css) but there is also a copy of all files located in the sources/ folder and a copy of django admin static files. How can I get only the minified file in the STATIC_ROOT folder?

Answer 1

You can create your own STATICFILES_STORAGE class, inherited from PipelineStorage , which expand the behavior of PipelineMixin . Something like this (need to be tested):

import shutil
import os.path

from django.conf import settings
from pipeline.storage import PipelineStorage

class PipelineCleanerStorage(PipelineStorage):
    def post_process(self, paths, dry_run=False, **options):
        # Do the usual stuff (compress and deliver)
        res = PipelineStorage.post_process(self, paths, dry_run=False, **options)

        # Clean sources files there
        shutil.rmtree(os.path.join(settings.BASE_DIR, "static/sources"))

        yield res

and use it in your settings.py instead of PipelineStorage .

Another way could be to run an automated task to clean this directory after each collectstatic. It would be the same idea but on the manage command itself.