I want to search a string(formed by concatenation of string and a regex) in another string.If the 1st string is present in the second string then i want to get the starting and ending addresses of matched phrase. For in the following code I want to search "baby accessories India" in "baby_NN accessories_NNS India_NNP is_VBZ an_DT online_JJ shopping_NN portal_NN " and want to get "baby_NN accessories_NNS India_NNP" as result.
import java.io.*;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class RegexMatching {
public static void main(String aaa[])throws IOException
{
String line="baby accessories India";
String []str=line.split("\\ ");
String temp="";
int i,j;
j=0;
String regEx1 = "([A-Z]+)[$]?";
for(i=0;i<str.length;i++)
temp=temp+str[i]+"_"+regEx1+" ";
String para2="baby_NN accessories_NNS India_NNP is_VBZ an_DT online_JJ shopping_NN portal_NN ";
Pattern pattern1 = Pattern.compile(temp);
Matcher matcher1 = pattern1.matcher(para2);
if (para2.matches(temp)) {
i = matcher1.start();
j = matcher1.end();
String temp1=para2.substring(i,j);
System.out.println(temp1);
}
else {
System.out.println("Error");
}
}
}
Try with Matcher#find()
if (matcher1.find())
instead of String#matches() that matches for whole string not just part of it.
if (para2.matches(temp))
output:
baby_NN accessories_NNS India_NNP
One more changes
if (matcher1.find()) {
i = matcher1.start();
j = matcher1.end();
String temp1 = para2.substring(i, j-1); // Use (j-1) to skip last space character
System.out.println(temp1);
}
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