Java extract text from job descriptions (Regex OR Pattern)

Question

In my text there will be content like:

2 years of experiences of databse, XXXBBXBXB 3 years databse and sql experiences, 
UUYFS 3 year experiences, 4 yeears databse contract, 5 years contract

What I want is to find the pattern of and get the single digit before the pattern:

1: years of experience
2: year of experiences
...

There will be the case that some text will be between the 'years' and 'experience'. And it might be appear as 'years' OR 'year' OR 'year experiences' and so on.

But the final output will be looks like: (excluding the digits with other patterns like 'years contract' and so on)

2, 3, 3

I tried something like '\\years\\experience', but seems it is wrong.

Any help? Thanks

Answer 1

Try with below regex

(\d+)\s+(year|years)

Get the digit at group 1 using Matcher#group() that looks for the groups enclosed in parenthesis ().

Read more about Java Regex Pattern

DEMO

Sample code:

String url = "2 years of experiences of databse, XXXBBXBXB 3 years databse and sql experiences, UUYFS 3 year experiences";
Pattern pattern = Pattern.compile("(\\d+)\\s+(year|years)");
Matcher matcher = pattern.matcher(url);

while (matcher.find()) {
    System.out.println(matcher.group(1));
}

output:

2
3
3

EDIT:

Try below pattern as per your comment:

(\d+)\s+(years of experience|year experience)

Answer 2

我认为您正在寻找这样的东西：

(\d+)\s+years?\s+.*?\s+experience