How can I get the IP address from a NIC (network interface controller) in Python?

Question

When an error occurs in a Python script on Unix, an email is sent.

I have been asked to add {Testing Environment} to the subject line of the email if the IP address is 192.168.100.37 which is the testing server. This way we can have one version of a script and a way to tell if the email is coming from messed up data on the testing server.

However, when I google I keep finding this code:

import socket
socket.gethostbyname(socket.gethostname())

However, that's giving me the IP address of 127.0.1.1. When I use ifconfig I get this

eth0      Link encap:Ethernet  HWaddr 00:1c:c4:2c:c8:3e
          inet addr:192.168.100.37  Bcast:192.168.100.255  Mask:255.255.255.0
          UP BROADCAST RUNNING MULTICAST  MTU:1500  Metric:1
          RX packets:75760697 errors:0 dropped:411180 overruns:0 frame:0
          TX packets:23166399 errors:0 dropped:0 overruns:0 carrier:0
          collisions:0 txqueuelen:1000
          RX bytes:59525958247 (59.5 GB)  TX bytes:10142130096 (10.1 GB)
          Interrupt:19 Memory:f0500000-f0520000

lo        Link encap:Local Loopback
          inet addr:127.0.0.1  Mask:255.0.0.0
          UP LOOPBACK RUNNING  MTU:16436  Metric:1
          RX packets:25573544 errors:0 dropped:0 overruns:0 frame:0
          TX packets:25573544 errors:0 dropped:0 overruns:0 carrier:0
          collisions:0 txqueuelen:0
          RX bytes:44531490070 (44.5 GB)  TX bytes:44531490070 (44.5 GB)

Firstly, I don't know where it got 127.0.1.1 from, but either way that's not what I want. When I google I keep coming to the same syntax, Bash scripts or netifaces and I'm trying to use standard libraries.

So how can I get the IP address of eth0 in Python?

Answer 1

Two methods:

Method #1 (use external package)

You need to ask for the IP address that is bound to your eth0 interface. This is available from the netifaces package

import netifaces as ni
ni.ifaddresses('eth0')
ip = ni.ifaddresses('eth0')[ni.AF_INET][0]['addr']
print(ip)  # should print "192.168.100.37"

You can also get a list of all available interfaces via

ni.interfaces()

Method #2 (no external package)

Here's a way to get the IP address without using a python package:

import socket
import fcntl
import struct

def get_ip_address(ifname):
    s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
    return socket.inet_ntoa(fcntl.ioctl(
        s.fileno(),
        0x8915,  # SIOCGIFADDR
        struct.pack('256s', ifname[:15])
    )[20:24])

get_ip_address('eth0')  # '192.168.0.110'

Note: detecting the IP address to determine what environment you are using is quite a hack. Almost all frameworks provide a very simple way to set/modify an environment variable to indicate the current environment. Try and take a look at your documentation for this. It should be as simple as doing

if app.config['ENV'] == 'production':
  #send production email
else:
  #send development email

Answer 2

Alternatively, if you want to get the IP address of whichever interface is used to connect to the network without having to know its name, you can use this:

import socket
def get_ip_address():
    s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
    s.connect(("8.8.8.8", 80))
    return s.getsockname()[0]

I know it's a little different than your question, but others may arrive here and find this one more useful. You do not have to have a route to 8.8.8.8 to use this. All it is doing is opening a socket, but not sending any data.

Answer 3

A simple approach which returns a string with ip-addresses for the interfaces is:

from subprocess import check_output

ips = check_output(['hostname', '--all-ip-addresses'])

for more info see hostname .

Answer 4

Since most of the answers use ifconfig to extract the IPv4 from the eth0 interface, which is deprecated in favor of ip addr , the following code could be used instead:

import os

ipv4 = os.popen('ip addr show eth0 | grep "\<inet\>" | awk \'{ print $2 }\' | awk -F "/" \'{ print $1 }\'').read().strip()
ipv6 = os.popen('ip addr show eth0 | grep "\<inet6\>" | awk \'{ print $2 }\' | awk -F "/" \'{ print $1 }\'').read().strip()

---

Alternatively, you can shift part of the parsing task to the python interpreter by using split() instead of grep and awk, as @serg points out in the comment:

import os

ipv4 = os.popen('ip addr show eth0').read().split("inet ")[1].split("/")[0]
ipv6 = os.popen('ip addr show eth0').read().split("inet6 ")[1].split("/")[0]

But in this case you have to check the bounds of the array returned by each split() call.

---

Another version using regex:

import os
import re

ipv4 = re.search(re.compile(r'(?<=inet )(.*)(?=\/)', re.M), os.popen('ip addr show eth0').read()).groups()[0]
ipv6 = re.search(re.compile(r'(?<=inet6 )(.*)(?=\/)', re.M), os.popen('ip addr show eth0').read()).groups()[0]

Answer 5

If you only need to work on Unix, you can use a system call (ref. Stack Overflow question Parse ifconfig to get only my IP address using Bash ):

import os
f = os.popen('ifconfig eth0 | grep "inet\ addr" | cut -d: -f2 | cut -d" " -f1')
your_ip=f.read()

Answer 6

Building on the answer from @jeremyjjbrown, another version that cleans up after itself as mentioned in the comments to his answer. This version also allows providing a different server address for use on private internal networks, etc..

import socket

def get_my_ip_address(remote_server="google.com"):
    """
    Return the/a network-facing IP number for this system.
    """
    with socket.socket(socket.AF_INET, socket.SOCK_DGRAM) as s: 
        s.connect((remote_server, 80))
        return s.getsockname()[0]

Answer 7

try below code, it works for me in Mac10.10.2:

import subprocess

if __name__ == "__main__":
    result = subprocess.check_output('ifconfig en0 |grep -w inet', shell=True) # you may need to use eth0 instead of en0 here!!!
    print 'output = %s' % result.strip()
    # result = None
    ip = ''
    if result:
        strs = result.split('\n')
        for line in strs:
            # remove \t, space...
            line = line.strip()
            if line.startswith('inet '):
                a = line.find(' ')
                ipStart = a+1
                ipEnd = line.find(' ', ipStart)
                if a != -1 and ipEnd != -1:
                    ip = line[ipStart:ipEnd]
                    break
    print 'ip = %s' % ip

Answer 8

Yet another way of obtaining the IP Address from a NIC, using Python.

I had this as part of an app that I developed long time ago, and I didn't wanted to simply git rm script.py . So, here I provide the approach, using subprocess and list comprehensions for the sake of functional approach and less lines of code:

import subprocess as sp

__version__ = "v1.0"                                                            
__author__ = "@ivanleoncz"

def get_nic_ipv4(nic):                                                          
    """
        Get IP address from a NIC.                                              

        Parameter
        ---------
        nic : str
            Network Interface Card used for the query.                          

        Returns                                                                 
        -------                                                                 
        ipaddr : str
            Ipaddress from the NIC provided as parameter.                       
    """                                                                         
    result = None                                                               
    try:                                                                        
        result = sp.check_output(["ip", "-4", "addr", "show", nic],             
                                                  stderr=sp.STDOUT)
    except Exception:
        return "Unkown NIC: %s" % nic
    result = result.decode().splitlines()
    ipaddr = [l.split()[1].split('/')[0] for l in result if "inet" in l]        
    return ipaddr[0]

Additionally, you can use a similar approach for obtaining a list of NICs:

def get_nics():                                                                 
    """                                                                         
        Get all NICs from the Operating System.                                 

        Returns                                                                 
        -------                                                                 
        nics : list                                                             
            All Network Interface Cards.                                        
    """                                                                         
    result = sp.check_output(["ip", "addr", "show"])                            
    result = result.decode().splitlines()                                       
    nics = [l.split()[1].strip(':') for l in result if l[0].isdigit()]          
    return nics                                                

Here's the solution as a Gist .

And you would have something like this:

$ python3
Python 3.6.7 (default, Oct 22 2018, 11:32:17) 
[GCC 8.2.0] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> 
>>> 
>>> import helpers
>>> 
>>> helpers.get_nics()
['lo', 'enp1s0', 'wlp2s0', 'docker0']
>>> helpers.get_nic_ipv4('docker0')
'172.17.0.1'
>>> helpers.get_nic_ipv4('docker2')
'Unkown NIC: docker2'

Answer 9

This will gather all IPs on the host and filter out loopback/link-local and IPv6. This can also be edited to allow for IPv6 only, or both IPv4 and IPv6, as well as allowing loopback/link-local in IP list.

from socket import getaddrinfo, gethostname
import ipaddress

def get_ip(ip_addr_proto="ipv4", ignore_local_ips=True):
    # By default, this method only returns non-local IPv4 Addresses
    # To return IPv6 only, call get_ip('ipv6')
    # To return both IPv4 and IPv6, call get_ip('both')
    # To return local IPs, call get_ip(None, False)
    # Can combime options like so get_ip('both', False)

    af_inet = 2
    if ip_addr_proto == "ipv6":
        af_inet = 30
    elif ip_addr_proto == "both":
        af_inet = 0

    system_ip_list = getaddrinfo(gethostname(), None, af_inet, 1, 0)
    ip_list = []

    for ip in system_ip_list:
        ip = ip[4][0]

        try:
            ipaddress.ip_address(str(ip))
            ip_address_valid = True
        except ValueError:
            ip_address_valid = False
        else:
            if ipaddress.ip_address(ip).is_loopback and ignore_local_ips or ipaddress.ip_address(ip).is_link_local and ignore_local_ips:
                pass
            elif ip_address_valid:
                ip_list.append(ip)

    return ip_list

print(f"Your IP Address is: {get_ip()}")

Returns Your IP Address is: ['192.168.1.118']

If I run get_ip('both', False), it returns

Your IP Address is: ['::1', 'fe80::1', '127.0.0.1', '192.168.1.118', 'fe80::cb9:d2dd:a505:423a']

Answer 10

It worked for me

 import subprocess
 my_ip = subprocess.Popen(['ifconfig eth0 | awk "/inet /" | cut -d":" -f 2 | cut -d" " -f1'], stdout=subprocess.PIPE, shell=True)
 (IP,errors) = my_ip.communicate()
 my_ip.stdout.close()
 print IP

Answer 11

Find the IP address of the first eth/wlan entry in ifconfig that's RUNNING:

import itertools
import os
import re

def get_ip():
    f = os.popen('ifconfig')
    for iface in [' '.join(i) for i in iter(lambda: list(itertools.takewhile(lambda l: not l.isspace(),f)), [])]:
        if re.findall('^(eth|wlan)[0-9]',iface) and re.findall('RUNNING',iface):
            ip = re.findall('(?<=inet\saddr:)[0-9\.]+',iface)
            if ip:
                return ip[0]
    return False

Answer 12

This is the result of ifconfig:

pi@raspberrypi:~ $ ifconfig
eth0: flags=4163<UP,BROADCAST,RUNNING,MULTICAST>  mtu 1500
        inet 192.168.2.24  netmask 255.255.255.0  broadcast 192.168.2.255
        inet6 fe80::88e9:4d2:c057:2d5f  prefixlen 64  scopeid 0x20<link>
        ether b8:27:eb:d0:9a:f3  txqueuelen 1000  (Ethernet)
        RX packets 261861  bytes 250818555 (239.1 MiB)
        RX errors 0  dropped 6  overruns 0  frame 0
        TX packets 299436  bytes 280053853 (267.0 MiB)
        TX errors 0  dropped 0 overruns 0  carrier 0  collisions 0

lo: flags=73<UP,LOOPBACK,RUNNING>  mtu 65536
        inet 127.0.0.1  netmask 255.0.0.0
        inet6 ::1  prefixlen 128  scopeid 0x10<host>
        loop  txqueuelen 1000  (Local Loopback)
        RX packets 74  bytes 16073 (15.6 KiB)
        RX errors 0  dropped 0  overruns 0  frame 0
        TX packets 74  bytes 16073 (15.6 KiB)
        TX errors 0  dropped 0 overruns 0  carrier 0  collisions 0

wlan0: flags=4099<UP,BROADCAST,MULTICAST>  mtu 1500
        ether b8:27:eb:85:cf:a6  txqueuelen 1000  (Ethernet)
        RX packets 0  bytes 0 (0.0 B)
        RX errors 0  dropped 0  overruns 0  frame 0
        TX packets 0  bytes 0 (0.0 B)
        TX errors 0  dropped 0 overruns 0  carrier 0  collisions 0

pi@raspberrypi:~ $ 

Cutting a bit the output, we have:

pi@raspberrypi:~ $ 
pi@raspberrypi:~ $ ifconfig eth0 | grep "inet 192" | cut -c 14-25
192.168.2.24
pi@raspberrypi:~ $ 
pi@raspberrypi:~ $ 

Now, we can go to python and do:

import os
mine = os.popen('ifconfig eth0 | grep "inet 192" | cut -c 14-25')
myip = mine.read()
print (myip)

Answer 13

If you want to do it the hard (but maybe fast?) way, here's some rough netlink (rfc3549) code (probably linux only) which gets both ipv4 and ipv6, with just one import statement from the standard library:

    import socket
    # https://www.man7.org/linux/man-pages/man7/rtnetlink.7.html
    # https://github.com/torvalds/linux/blob/master/include/uapi/linux/rtnetlink.h
    RTM_NEWADDR = 20
    RTM_GETADDR = 22
    # https://www.man7.org/linux/man-pages/man7/netlink.7.html
    # https://github.com/torvalds/linux/blob/master/include/uapi/linux/netlink.h
    NLM_F_REQUEST = 0x01
    NLM_F_ROOT = 0x100
    s = socket.socket(socket.AF_NETLINK, socket.SOCK_RAW)
    req = (
        # nlmsghdr
        int.to_bytes(0, 4, 'little', signed=False) +  # nlmsg_len
        int.to_bytes(RTM_GETADDR, 2, 'little', signed=False) +  # nlmsg_type
        int.to_bytes(NLM_F_REQUEST | NLM_F_ROOT, 2, 'little', signed=False) +  # nlmsg_flags
        int.to_bytes(0, 2, 'little', signed=False) +  # nlmsg_seq
        int.to_bytes(0, 2, 'little', signed=False) +  # nlmsg_pid
        # ifinfomsg
        b'\0' * 8
    )
    req = int.to_bytes(len(req), 4, 'little') + req[4:]
    s.sendall(req)
    full_resp = s.recv(4096)
    while full_resp:
        resp = full_resp
        # nlmsghdr
        nlmsg_len = int.from_bytes(resp[0:4], 'little', signed=False)
        nlmsg_type = int.from_bytes(resp[4:6], 'little', signed=False)
        assert not nlmsg_len % 4, nlmsg_len
        resp = resp[16:nlmsg_len]
        full_resp = full_resp[nlmsg_len:]
        if nlmsg_type == 3:  # NLMSG_DONE
            assert not full_resp, full_resp
            break
        if not full_resp:
            full_resp = s.recv(4096)
        assert nlmsg_type == RTM_NEWADDR, (nlmsg_type, resp[:32])
        # ifaddrmsg
        ifa_family = int.from_bytes(resp[0:1], 'little', signed=False)
        ifa_index = int.from_bytes(resp[4:8], 'little', signed=False)
        resp = resp[8:]
        while resp:
            # rtattr
            rta_len = int.from_bytes(resp[0:2], 'little', signed=False)
            rta_type = int.from_bytes(resp[2:4], 'little', signed=False)
            data = resp[4:rta_len]
            if rta_type == 1:  # IFLA_ADDRESS
                if ifa_family == socket.AF_INET:
                    ip = '.'.join('%d' % c for c in data)
                if ifa_family == socket.AF_INET6:
                    ip = ':'.join(('%02x%02x' % (chunk[0], chunk[1]) if chunk != b'\0\0' else '') for chunk in [data[0:2], data[2:4], data[4:6], data[6:8], data[8:10], data[10:12], data[12:14], data[14:16]])
                print('interface #%s has %s' % (ifa_index, ip))
            if rta_type == 3:  # IFLA_IFNAME
                ifname = data.rstrip(b'\0').decode()
                print('interface #%s is named %s' % (ifa_index, ifname))
            # need to round up to multiple of 4
            if rta_len % 4:
                rta_len += 4 - rta_len % 4
            resp = resp[rta_len:]
    s.close()

If you just need ipv4, the oldschool SIOCGIFADDR ioctl method in another answer is probably more straightforward. For ipv6, there's /proc/net/if_inet6 .

Answer 14

Answer using psutil :

import psutil
import socket

def get_ipv4_from_nic(interface):
    interface_addrs = psutil.net_if_addrs().get(interface) or []
    for snicaddr in interface_addrs:
        if snicaddr.family == socket.AF_INET:
            return snicaddr.addressinterface_addrs]

Example:

>>> get_ipv4_from_nic("eth0")
'192.168.100.37'

Answer 15

try this:

import netifaces as ni

def test_netowrk(): interfaces = ni.interfaces()

for i in interfaces: #will cycle through all available interfaces and check each one. you can use anything for "i". its almost like saying import netifaces as ni. but i doesn't need to be declared, the systems assumes that for (what you put here) in interfaces means what you put there should resemble each of the results returned are represented by i.
    if i != "lo": #lo is the local loopback. This will remove lo from the interfaces it checks.
        try:
            ni.ifaddresses(i)
            gws = ni.gateways()
            gateway = gws['default'][ni.AF_INET][0]
            ip = ni.ifaddresses(i)[ni.AF_INET][0]['addr']
            sm = ni.ifaddresses(i)[ni.AF_INET][0]['netmask']
            print ("Network information for " + i + ":")
            print ("IP: " + ip)
            print ("Subnet Mask: " + sm)
            print ("Gateway: " + gateway)
            print ()
        except: #this is good to have in case you have a disconnected wifi or trying to test a network with no DHCP
            print (i + " is not connected or DHCP is not available. Try setting a static IP.")

test_netowrk()

results:

Network information for eth0:

IP: 192.168.1.172

Subnet Mask: 255.255.255.0

Gateway: 192.168.1.254

wlan0 is not connected or DHCP is not available.